Module Module1
Const PICWIDTH As Integer = 40
Const PICHEIGHT As Integer = 40
Sub fillPic(ByVal pic As Char(,), ByVal penColor As Char)
For y As Integer = 0 To pic.GetUpperBound(0)
For x As Integer = 0 To pic.GetUpperBound(0)
pic(x, y) = penColor
Next
Next
End Sub
Sub displayPic(ByVal pic As Char(,))
For y As Integer = 0 To pic.GetUpperBound(0)
For x As Integer = 0 To pic.GetUpperBound(1)
Console.Write(pic(x, y))
Next
Console.WriteLine()
Next
Console.ReadLine()
End Sub
Sub drawLine(ByVal pic As Char(,), ByVal penColor As Char, ByVal x1 As Integer, ByVal y1 As Integer, ByVal x2 As Integer, ByVal y2 As Integer)
Dim x, y As Integer
If x1 = x2 Then ' Vertical Line
' We need to have a special case for a vertical line.
' The reason we need to treat a vertical line differently
' is that the slope of a vertical line is undefined since you
' would have to divide by zero when calculating the slope.
' In mathematics (and in computer programming) it is
' an ERROR to divide by zero.
For y = y1 To y2
pic(x1, y) = penColor
Next
ElseIf y1 = y2 Then 'Horizontal Line
' The following is a special case for a horizontal line.
'
' In a strict mathematical sense we don't need to treat
' horizontal lines as a special case. However, our algorithm
' below will cause a division by zero error for horizontal
' lines too.
For x = x1 To x2
pic(x, y1) = penColor
Next
Else ' diagonal line
' Calculate the slope
Dim m As Double = (y2 - y1) / (x2 - x1)
' For every x value on the line calculate the appropriate
' y value and display it on the line
For x = x1 To x2
' The following comes from reorganizing the
' "point-slope" equation for a line, y-y1=m(x-x1),
' where x1,y1 is a SPECIFIC point, x is a "free variable" -
' i.e. x can take on any value and y is the value that
' is calculated from the specific value for x that
' is chosen
y = Math.Round(m * (x - x2) + y2)
pic(x, y) = penColor
Next
' For every y value on the line calculate the appropriate
' x value and display it on the line.
For y = y1 To y2
x = Math.Round((y - y2 + m * x2) / m)
pic(x, y) = penColor
Next
End If
End Sub
' Copy a portion of a picture and return a new picture with just that portion
Function copy(ByVal pic As Char(,), ByVal x As Integer, ByVal y As Integer, ByVal width As Integer, ByVal height As Integer) As Char(,)
Dim newPic As Char(,) = New Char(height, width) {}
For row As Integer = y To height
For col As Integer = x To width
newPic(row, col) = pic(y + row, x + col)
Next
Next
Return newPic
End Function
' Paste a copy of pic2 onto pic1 at a specific location
Sub paste(ByVal pic1 As Char(,), ByVal pic2 As Char(,), ByVal x As Integer, ByVal y As Integer)
For pic2row As Integer = 0 To pic2.GetUpperBound(0)
For pic2col As Integer = 0 To pic2.GetUpperBound(1)
pic1(pic2col + x, pic2row + y) = pic2(pic2col, pic2row)
Next
Next
End Sub
Sub Main()
Dim pics As Char()(,) = New Char(10)(,) {}
pics(0) = New Char(PICHEIGHT, PICWIDTH) {}
fillPic(pics(0), ".")
drawLine(pics(0), "1", 0, 0, PICWIDTH, 0)
drawLine(pics(0), "2", 0, 0, PICWIDTH, 10)
drawLine(pics(0), "3", 0, 0, PICWIDTH, 25)
drawLine(pics(0), "4", 0, 0, PICWIDTH, PICHEIGHT)
drawLine(pics(0), "5", 0, 0, 25, PICHEIGHT)
drawLine(pics(0), "6", 0, 0, 10, PICHEIGHT)
drawLine(pics(0), "7", 0, 0, 0, PICHEIGHT)
displayPic(pics(0))
pics(1) = New Char(10, 10) {}
fillPic(pics(1), "*")
displayPic(pics(1))
pics(2) = copy(pics(0), 0, 0, 10, 10)
displayPic(pics(2))
pics(3) = New Char(40, 40) {}
fillPic(pics(3), ".")
'paste(pics(3), pics(1), 0, 0)
'paste(pics(3), pics(2), 10, 0)
'paste(pics(3), pics(2), 0, 10)
'paste(pics(3), pics(1), 10, 10)
paste(pics(3), pics(1), 5, 5)
paste(pics(3), pics(2), 25, 5)
paste(pics(3), pics(2), 5, 25)
paste(pics(3), pics(1), 25, 25)
displayPic(pics(3))
End Sub
End Module